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Post by Host Blue on Jan 11, 2012 17:35:51 GMT -8
This challenge will take place in a series of 5 rounds. Each round you will choose either "Blue Tribe" or "Yellow Tribe." Abra can not participate, so there are 9 people participating. No matter how you decide to divvy up, there will always be one Tribe that has an even number of people and one that has an odd amount. In order to win this challenge, you must correctly choose the tribe with an odd number of people every time.
Example Round 1: ( A-G = players)
Blue's Tribe : A, B, C, D Yellow's Tribe: E, F, G
In the above example, Yellow's tribe, which has 3 players, would have the odd number . That means everyone from Blue's tribe is eliminated.
and we will keep going until we have only 1 person standing in one of the tribes (either Blue or Yellow's ) .
This is a simple and fun challenge . In order to do it make a thread in your confessional called IC #15 or something like that and add the rounds.
Round 1
Round 2
Round 3
Round 4
Round 5
and post the name you want next to the round .
For example lets imagine that we are talking about about Red and Green's tribe
Round 1 - Green
Round 2 - Green
Round 3- Red
Round 4 - Green
Round 5 - Red
Its pretty much like that . You will have 24 hours to do this challenge . Good luck guys
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Post by Tauros on Jan 11, 2012 19:50:56 GMT -8
yeah i dont understand lol
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Post by Sandshrew - 10th Jury Member on Jan 11, 2012 20:41:48 GMT -8
Basically, choose a random team. If at the end of the round, there are an odd number of people on your team you win. On that note... anyone read liar game?
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